Play with List of dictionaries in Python

Sort a list of dictionaries in Python based on a specific key

list_of_dicts = [
    {"folder_name": "C", "other_key": "value1"},
    {"folder_name": "A", "other_key": "value2"},
    {"folder_name": "B", "other_key": "value3"}
]

sorted_list = sorted(list_of_dicts, key=lambda x: x['folder_name'])

>>> sorted_list 
[
    {"folder_name": "A", "other_key": "value2"},
    {"folder_name": "B", "other_key": "value3"}
    {"folder_name": "C", "other_key": "value1"},
]

Extract a list of values from a list of dictionaries based on a specific key

list_of_dicts = [
    {"folder_name": "C", "other_key": "value1"},
    {"folder_name": "A", "other_key": "value2"},
    {"folder_name": "B", "other_key": "value3"}
]

folder_names_list = [d['folder_name'] for d in list_of_dicts]
other_keys_list = [d['other_key'] for d in list_of_dicts]

>>> folder_names_list
['C', 'A', 'B']

>>> other_keys_list
['value1', 'value2', 'value3']

Flaten List of Lists

list_of_lists = [[1, 2, 3], [4, 5], [6, 7, 8, 9]]

flattened_list = [item for sublist in list_of_lists for item in sublist]

>>> flattened_list
[1, 2, 3, 4, 5, 6, 7, 8, 9]

Recommended:

from itertools import chain

list_of_lists = [[1, 2, 3], [4, 5], [6, 7, 8, 9]]
flattened_list = list(chain.from_iterable(list_of_lists))

>>> flattened_list
[1, 2, 3, 4, 5, 6, 7, 8, 9]

Written by - Dishant Sethi

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